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6x^-5x^2-44x+15=0
We add all the numbers together, and all the variables
-5x^2-38x+15=0
a = -5; b = -38; c = +15;
Δ = b2-4ac
Δ = -382-4·(-5)·15
Δ = 1744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1744}=\sqrt{16*109}=\sqrt{16}*\sqrt{109}=4\sqrt{109}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-4\sqrt{109}}{2*-5}=\frac{38-4\sqrt{109}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+4\sqrt{109}}{2*-5}=\frac{38+4\sqrt{109}}{-10} $
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